All categories

3 years ago

Roger drives 256km and uses 20l of fuel. what is his average fuel consumption for 100km?

Mathematics

1 answer:

Bezzdna [24]3 years ago

3 0

Answer:

7. 8125 l

Step-by-step explanation:

256 km ....... 20l

100 km ...........x l

x = 100×20/256

= 7. 8125 l

You might be interested in

An aircraft takes off and climbs at a constant 30° angle until it reaches an altitude of 6 miles.

Firlakuza [10]

Answer:

10.4 miles

Step-by-step explanation:

Let the horizontal distance is x

<u>Use tangent to solve this:</u>

tan 30° = 6/x
x = 6 / tan 30°
x = 10.4 mi (rounded)

5 0

3 years ago

Highest/greatest common factor of 50 and 125

Nata [24]

50 =2×5×5 125=5×5×5 Hoghest common factor = 5×5 =25

5 0

3 years ago

Read 2 more answers

Find the length of line segmentAB which joins the following points.A(10, 14) and B(2,6)

Helen [10]

Answer:

The equation of the line AB is y - x -4 = 0

Step-by-step explanation:

The points are A (10,14) and B(2,6)

Now, slope of the line AB : $m = \frac{y_2 - y_1}{x_2 - x_1}$

or, $m = \frac{14 -6 }{10 - 2}$ = $\frac{8}{8} = 1$

So, slope of the equation AB = 1

Now, by SLOPE INTERCEPT FORM:

The equation of line is given as : y - y0 = m (x-x0)

So,the equation of line AB is y - 6 = 1(x-2)

or, y - 6 -x + 2 = 0

or, y - x -4 = 0

Hence, the equation of the line AB is y - x -4 = 0

5 0

3 years ago

X^8+1 divided by 2x+1

Alina [70]

Answer:

x8+12

x+1

Step-by-step explanation:

3 0

3 years ago

16 POINTS!!! HELP ASAP

nadya68 [22]

Answer:

The answer is 358.01

Step-by-step explanation:

Given:

$3\times 10^{2}+5\times 10^{1}+8\times 10^{0}+1\times \frac{1}{10^{2}}$

Now, to solve first we crack the power notation then multiply and then do the addition:

$3\times 100+5\times 10+8\times 1+1\times \frac{1}{100}$

(The value of $10^{1}$ is 10 and the value of $10^{0}$ is 1.)

$=300+50+8+\frac{1}{100}$

$=300+50+8+0.01$

$=358.01$ .

Therefore, the answer is 358.01 .

7 0

3 years ago