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dem82 [27]
3 years ago
5

How to write 309,017 in word form

Mathematics
2 answers:
7nadin3 [17]3 years ago
5 0
Three hundred nine thousand seventeen
dalvyx [7]3 years ago
3 0
Three hundred and nine thousand and seventeen
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Uhhh what is 2+2-2+2
Ierofanga [76]

Its 4 because 2+2 is 4 and then you're subtracting 2 and then adding 2 again so its 4

4 0
3 years ago
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What are these questions i need help
Over [174]

The roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

<h3>What are quadratic equations?</h3>

Quadratic equations are equations that have a second degree and have the standard form of ax^2 + bx + c = 0, where a, b and c are constants and the variable a does not equal 0

<h3>How to determine the other roots of the equation?</h3>

The equation of the function is given as:

f(x) = x^2 - 93987

The above equation is a quadratic equation

Express the equation as a difference of two squares

f(x) = (x - √93987)(x + √93987)

Set the equation of the function to 0

(x - √93987)(x + √93987) = 0

Split the factors of the above function equation as follows

x - √93987 = 0 and x + √93987 = 0

Solve for x in the above equations

x = √93987 and x = -√93987

Hence, the roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

Read more about roots of equation at

brainly.com/question/776122

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5 0
1 year ago
I need help with number 3
Juli2301 [7.4K]

Answer:

a) 8 apples

b) 5 oranges

c) 2 oranges and 6 apples

Step-by-step explanation:

a) 8 apples × 1$ = 8$ < 10$

b) 5 oranges × 2$ = 10$

c) 2 oranges × 2$ = 4$

6 apples × 1$ = 6$ (4+6=10)

7 0
3 years ago
Read 2 more answers
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
A motel bills its customers by charging a flat fee for the first night and then adding on a fixed amount for every night thereaf
melamori03 [73]
65 is the flat fee for the first night followed by a charge of 45 a night.
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