Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
The median is 38.5
The lower quartile is 29
There is an outlier (154)
The upper quartile is 70
and
The interquartile range is 70 - 29 = 41
Answer:
30%
Step-by-step explanation:
Well since we know that 45% is vanilla that means we have part of our answer
Also we know we sold 1/4 strawberry which in percent that would be 25%
If we add 45% with 25% 45+25=70 then since something can only be 100%
100%-70%=30%
you sold 30% chocolate
<3 <;
First we must change these numbers to improper fractions:
![2\frac{4}{7}=\frac{18}{7}](https://tex.z-dn.net/?f=%202%5Cfrac%7B4%7D%7B7%7D%3D%5Cfrac%7B18%7D%7B7%7D%20)
![1\frac{3}{6}=\frac{9}{6}](https://tex.z-dn.net/?f=%201%5Cfrac%7B3%7D%7B6%7D%3D%5Cfrac%7B9%7D%7B6%7D%20)
So then we set it up:
÷ ![\frac{9}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B6%7D%20)
When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:
![\frac{18}{7}*\frac{6}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B7%7D%2A%5Cfrac%7B6%7D%7B9%7D%20)
Then we solve:
![\frac{108}{63}](https://tex.z-dn.net/?f=%20%5Cfrac%7B108%7D%7B63%7D%20)
Then if we divide the numerator and the denominator by 9, we get:
or, in mixed-number form,
.