X^2+4x=-3
x^2+4x+3=0
(x+1)(x+3)=0
x+1=0 so x=-1
x+3=0 so x=-3
so the solution is x=-3,-1
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Answer:
y=-8/3x-11 is the equation of the line and the value of y
Step-by-step explanation:
Use point slope form m = y-y1/x-x1, or y-y1=m(x-x1)
Find the slope from the two points (-6,5) and (-3,-3)
m = y2-y1/x2-x1 = -3-5/-3+6 = -8/3
use one point say (-6,5) that passes through the line and the slope to form the equation y-5=-8/3(x+6) rearrange y= -8/3(x+6)+5
y=-8/3x - 48/3 +5 = -8/3x-16+5 = -8/3x-11
Answer:
Step-by-step explanation:
<h3>Arithmetic sequence:</h3>
6th term is 14 ⇒ 
a + (6 - 1)d = 14
a + 5d = 14 --------------(I)
14th term is 6 ⇒
a + (14-1)d = 6
a + 13d = 6 ----------------(II)
Subtract equation (II) from equation(I)
(I) a + 5d = 14
(II) a + 13d = 6
<u>- - -</u>
-8d = 8
d = 8 ÷(-8)
Plugin d = -1 in equation (I)
a + 5(-1) = 14
a -5 = 14
a = 14 + 5
20th term:
= 19 - 19
X=amount of money Ofeila hasx-$12=(1/5)xLet's eliminate the fractions by multiplying both sides by 5...5(x-$12)=(5)(1/5)x5x-$60=xLet's subtract 5x from both sides...-5x+5x-$60=x-5x-$60=-4xLet's divide both sides by -4...(-$60)/(-4)=(-4x)/(-4)$15=x -< AnswerLet's check our work...x-$12=(1/5)x$15-$12=(1/5)($15)$3=$3
Answer:
A. BC ≈ 2.52; AB ≈ 1.28; m∠C = 27°
B. BC ≈ 1.28; AB ≈ 2.52; m∠C = 27°
C. BC ≈ 2.52; AB ≈ 1.28; m∠C = 117°
D. BC ≈ 1.28; AB ≈ 2.52; m∠C = 117°
