Hi there! Hopefully this helps!
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<em>Answer to the first equation:</em><u><em> 3.</em></u>
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<em>Answer to the second equation: </em><u><em>7</em></u>
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<em>Answer to the third equation: </em><u><em>-2.</em></u>
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<em>Answer to the fourth equation: </em><u><em>-3</em></u>
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Translating that problem into an equation with x as a variable we get 3x + x +10 = 22. Combine like terms to get 4x + 10 = 22. Subtract 10 on both sides to get 4x = 12. Divide by 4 on both sides to get x = 3.
Now to plug in. The first number was represented by 3x. So substituting 3 for the x we get 3(3) = 9. And again for the second number represented by x+10, 3+10 = 13.
Your numbers are 9 and 13. To check just add them together. 13 + 9 is 22, I'll save ya the effort.
Step-by-step explanation:
For solving, use quadratic formula
False ....a parameter is something YOU can change, like asking magazines if they are interested in sports, or interested in photography, or something else. So the 12% is a statistic.
Factors are (y - 7)(5y - 43)
Step-by-step explanation:
- Step 1: Given, 5x² + 12x + 4 = (x + 2)(5x + 2)
Now, to factor 5(y - 9)² + 12(y - 9) + 4. Here, y - 9 can be equated to x if both equations are compared.
- Step 2: To factorize, substitute y - 9 for x in the factors (x + 2)(5x + 2)
⇒ Factors = (y - 9 + 2)[5(y - 9) + 2]
= (y - 7)(5y - 45 + 2)
= (y - 7)(5y - 43)
