Here is the graph. I marked the maximum point and the axis intercept.
Answer:
The probability that the diagnosis is correct is 0.95249.
Step-by-step explanation:
We are given that the American Diabetes Association estimates that 8.3% of people in the United States have diabetes.
Suppose that a medical lab has developed a simple diagnostic test for diabetes that is 98% accurate for people who have the disease and 95% accurate for people who do not have it.
Let the probability that people in the United States have diabetes = P(D) = 0.083.
So, the probability that people in the United States do not have diabetes = P(D') = 1 - P(D) = 1 - 0.083 = 0.917
Also, let A = <u><em>event that the diagnostic test is accurate</em></u>
So, the probability that a simple diagnostic test for diabetes is accurate for people who have the disease = P(A/D) = 0.98
And the probability that a simple diagnostic test for diabetes is accurate for people who do not have the disease = P(A/D') = 0.95
<u>Now, the probability that the diagnosis is correct is given by; </u>
Probability = P(D)
P(A/D) + P(D')
P(A/D')
= (0.083
0.98) + (0.917
0.95)
= 0.08134 + 0.87115
= 0.95249
Hence, the probability that the diagnosis is correct is 0.95249.
Answer:
B) ![8\sqrt[4]{4}](https://tex.z-dn.net/?f=8%5Csqrt%5B4%5D%7B4%7D)
Step-by-step explanation:
![(2^{8} *2^{6} )^\frac{1}{4} = (2^{8+6} )^\frac{1}{4} =(2^{14} )^\frac{1}{4} =2^{\frac{7}{2} }=\sqrt{2^{7} } =2^{3} \sqrt{2} =8\sqrt{2} = 8\sqrt[4]{2^{2} } = 8\sqrt[4]{4}](https://tex.z-dn.net/?f=%282%5E%7B8%7D%20%2A2%5E%7B6%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D%20%282%5E%7B8%2B6%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D%282%5E%7B14%7D%20%29%5E%5Cfrac%7B1%7D%7B4%7D%20%3D2%5E%7B%5Cfrac%7B7%7D%7B2%7D%20%7D%3D%5Csqrt%7B2%5E%7B7%7D%20%7D%20%20%3D2%5E%7B3%7D%20%5Csqrt%7B2%7D%20%3D8%5Csqrt%7B2%7D%20%3D%208%5Csqrt%5B4%5D%7B2%5E%7B2%7D%20%7D%20%3D%208%5Csqrt%5B4%5D%7B4%7D)
8:24
4:12
100:300
All you have to do is multiply both sides by the same number to get an equivalent ratio.
Answer:
Negative with little correlation
It has negative slope if you imagine a line