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cestrela7 [59]
3 years ago
5

How do i plot the locus of points for x=y.

Mathematics
1 answer:
aniked [119]3 years ago
8 0
The locus means the “set of all” so the locus off points where x = y is all points where the x and y coordinate are the same.

One example is (1,1). Another is (2,2). Here the point (x,y) has the same number for x as for y. If you plot a few points (1,1), (2,2), (3,3) you will see they all fall on the same line. It is a diagonal line with positive slope that divides the first and third quadrants exactly in half.

For x=3 we find points where the first number (the x coordinate) is 3. The second number can be anything. Some points are (3,1) (3,2) (3,3). These points all lie on a vertical line that intersects the x axis at 3.
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Solve: 2x+7/5 - x-3/10 = x+1/15<br>find the value of x and verify the result will RHS ​
choli [55]

Step-by-step explanation:

<h3><u>Given Question :- </u></h3>

Solve for x :-

\dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}  =  \dfrac{x + 1}{15}

\red{\large\underline{\sf{Solution-}}}

Given linear equation is

\rm :\longmapsto\: \dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{2(2x + 7) - (x - 3)}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{4x + 14 - x  +  3}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{(4x - x)  + (14 + 3)}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{3x  + 17}{10}  =  \dfrac{x + 1}{15}

On multiply by 5 on both sides,

\rm :\longmapsto\: \dfrac{3x  + 17}{2}  =  \dfrac{x + 1}{3}

On cross multiplication, we get

\rm :\longmapsto\:3(3x + 17) = 2(x + 1)

\rm :\longmapsto\:9x +51 = 2x + 2

\rm :\longmapsto\:9x  - 2x = 2 - 51

\rm :\longmapsto\:7x = - 49

\bf\implies \:x =  - 7

<h3><u>VERIFICATION</u></h3>

Consider, LHS

\red{\rm :\longmapsto\: \dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}}

On substituting the value of x, we get

\red{\rm \:  =  \:  \dfrac{2( - 7) + 7}{5} -  \dfrac{ - 7 - 3}{10}}

\red{\rm \:  =  \:  \dfrac{ - 14 + 7}{5} -  \dfrac{ - 10}{10}}

\red{\rm \:  =  \:  \dfrac{ - 7}{5}  + 1}

\red{\rm \:  =  \:  \dfrac{ - 7 + 5}{5}}

\red{\rm \:  =  \:  \dfrac{ - 2}{5}}

Consider RHS

\green{\rm :\longmapsto\:\dfrac{x + 1}{15}}

On substituting the value of x, we get

\green{\rm \:  =  \: \dfrac{ - 7 + 1}{15}}

\green{\rm \:  =  \: \dfrac{ - 6}{15}}

\green{\rm \:  =  \: \dfrac{ - 2}{5}}

\rm \implies\:LHS=RHS

HENCE, VERIFIED

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The answer is D                  you need to compare all the gallons by year and how much they waste.

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