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3 years ago

Point J is on line segment IK. Given JK = 8 and IJ = 7, determine the length IK.

Mathematics

1 answer:

masha68 [24]3 years ago

3 0

Answer:

Step-by-step explanation:

If the line segment is IK, that means IJ+JK=IK. So, 7+8=15

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Find the solution for the system of linear equations by substitution: 2x - y = 3 y − x = 1

Leviafan [203]

The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the solution to the system?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x- y = 3

y - x = 1

Make y the subject in the second equation, by adding x to both sides of the equation

y - x + x = x + 1

This gives

y = x + 1

Substitute y = x + 1 in 2x- y = 3

2x- x - 1 = 3

Evaluate the like terms

x = 4

Substitute x = 4 in y = x + 1

y = 4 + 1

Evaluate

y = 5

Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5

Read more about system of linear equations at

brainly.com/question/14323743

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2 years ago

Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)

vekshin1

$\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}$

$\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )$

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3 years ago

An unknown number y is 12 more than an unknown number x. The number y is also x less than 17. The equations to find x and y are

grandymaker [24]

Answer:

d because then you can solve for y then use your answer to find x

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3 years ago

Read 2 more answers

Three boxes have a total weight of 640 pounds. Box A weights twice as much as Box B. Box C weight 30 pounds more than Box A. How

Zarrin [17]

Answer:

A: 244 pounds

B: 122 pounds

C: 274 pounds

Step-by-step explanation:

We have A+B+C = 640; A=2B; C=A+30. Substituting the last into the first gives ...

A + B + (A +30) = 640

2A +B = 610 . . . . . . . . . . . . subtract 30

Substituting the second into this equation gives ...

2(2B) +B = 610

B = 610/5 = 122 . . . . . divide by 5

A = 2B = 244 . . . . . . . .find A from B

C = A+30 = 274 . . . . . find C from A

Box A weighs 244 pounds; box B weighs 122 pounds; box C weighs 274 pounds.

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3 years ago

Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil

KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

= 6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

= 9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

= 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

= 4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

= 4.5 days to get to the next pond.

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3 years ago

Point J is on line segment IK. Given JK = 8 and IJ = 7, determine the length IK.​

Point J is on line segment IK. Given JK = 8 and IJ = 7, determine the length IK.