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Bond [772]
3 years ago
13

Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil

e per day. How many days will it take him to get there
Mathematics
1 answer:
KIM [24]3 years ago
3 0

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

   =  6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

   =  9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

   = 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

   =  4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

   =  4.5 days to get to the next pond.

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Answer:

Option C

Step-by-step explanation:

complete question

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The given equation can be written as

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Option C is correct

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2 years ago
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Alexxx [7]
Ok

y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate

set y=0
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use quadratic formula
if you have ax^2+bx+c=0, then
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you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
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The chess club members bought six tickets to a tournament for $15. how much would they have paid if all nine members wanted to g
ElenaW [278]
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Answer:

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