<h2>
Explanation:</h2>
In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:
So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:
Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m
Answer:
40 percent
Step-by-step explanation:
60 - 20 = 40
Reasoning: The amount of seniors that attended was 20 percent, so 60 (total students) percent minus 20 percent is equal to 40 percent.
Hope this helps!
Answer
(a) 
(b) 
Step-by-step explanation:
(a) 
δ(t)
where δ(t) = unit impulse function
The Laplace transform of function f(t) is given as:
where a = ∞
=> 
where d(t) = δ(t)
=> 
Integrating, we have:
=> 
Inputting the boundary conditions t = a = ∞, t = 0:
(b) 
The Laplace transform of function f(t) is given as:
Integrating, we have:
![F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.](https://tex.z-dn.net/?f=F%28s%29%20%3D%20%5B%5Cfrac%7B-e%5E%7B-%28s%20%2B%201%29t%7D%7D%20%7Bs%20%2B%201%7D%20-%20%5Cfrac%7B4e%5E%7B-%28s%20%2B%204%29%7D%7D%7Bs%20%2B%204%7D%20-%20%5Cfrac%7B%283%28s%20%2B%201%29t%20%2B%201%29e%5E%7B-3%28s%20%2B%201%29t%7D%29%7D%7B9%28s%20%2B%201%29%5E2%7D%5D%20%5Cleft%20%5C%7B%20%7B%7Ba%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
Inputting the boundary condition, t = a = ∞, t = 0:
The Z-score (z) is calculated according to the formula: z = (x - μ) / σ
Where: x is the raw score value, μ is the mean of the population, σ is the standard deviation of the population.
x = 80, μ = 5, σ = 4
z = (80 - 5) / 4
z = 75 / 4 = 18.7500
Z-score is 18.7500
