Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Answer:
25
Step-by-step explanation:
b=4x+1 h=x+1 A=175
A=bh
Substitute: 175=(4x+1)(x+1)
Expand: 175=4x^2+5x+1
Subtract 175
4x^2+5x-174=0
Solve w/quadratic formula
(-5 <u>+</u> sqrt(25+2784))/8
Simplify: x=6 or -29/4
Distance is positive, so x=6
4x+1=4*6+1=25
Answer:
1. X/2 = 4
2. 3x - 2 = 11
3. 2x - 5 = 15
4. 2x-1=12
5. 9x = 2(x+5)
Step-by-step explanation:
The question doesn't seem specific enough. If there are options, please list.
7.380 times 10 to the 9th power (or 7.38 times 10 to the 9th power)
