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3 years ago

2d+4=10+2.5d Help Me

1 answer:

6 0

Subtract 2d from both sides

simplify 10 + 2.5d - 2d to 10 + 0.5d

subtract 10 from both sides

simplify 4 - 10 to -6

divide both sides by 0.5

simplify 6/0.5 to 12

switch the sides

Answer: d = -12.

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago

VERY URGANT AS WELL

LuckyWell [14K]

430-18 not in index
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Margarita [4]

Answer: i think its 7b+7a+15 - a - 10 and 7(8j + 5) -12

Step-by-step explanation:

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vladimir1956 [14]

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