Alita is on the track team and loves to run. On

Five people each working 8 hours a day can assemble 400 toys in a 5 day work week. What is the average number of toys assembled

rjkz [21]

Step-by-step explanation: 2 per hour and per person because 8 x 5 is 40 so 400 divided by 40 equals 10 so then 10 divided by 5 is 2 so 2 per hour

4 0

3 years ago

How to solve using substitution y=3/4X+5 4x-3y=-1

Pachacha [2.7K]

Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as y=(3/4)X+5

Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:

4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)

Let 's now solve the system

4y=3x + 20
4x-3y=-1

We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:

12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)

Then we have

12y = 9x + 60
-12y =-16x - 4

If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8

We were given equations
y=3/4X+5
4x-3y=-1

We can subst. x=8 into either of these eqn's to find y. Let's try the first one:

y = (3/4)(8)+5 = 6+5=11

Then x=8 and y=11.

You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?

5 0

3 years ago

suppose your school sells a total of 1139 tickets for a basketball game. An adult ticket cost $5. A student ticket cost $1. The

Wewaii [24]

Answer:

look at picture

Step-by-step explanation:

x: adult tickets

y: student tickets

3 0

4 years ago

marlene is painting square tiles for a project.each tile has a perimeter of 16 in.what is the length of each side.

elixir [45]

Answer:

64 i hope im right

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

30 years ago

Zoe was 2/3 as old as Luke

18 years ago

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

30 years ago

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

18 years ago

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now