Question

Find the equation of the circle that has a diameter with endpoints (7,3) and (7,-5)

Answer 1

Answer:

(x-7)² + (y+1)² = 4² or (x-7)² + (y+1)² =16

Step-by-step explanation:

1) coordinates of the center

x0=(x1+x2)/2=(7+7)/2=7

y0=(y1+y1)/2=(3-5)/2 = -1

(7, -1) - coordinates of the center

2) radius of the circle

length of the diameter =√((x2-x1)²+(y2-y1)²)=√((7-7)²+(-5-3)²)=√(8)²= 8

r = length of the radius = length of the diameter / 2 = 8/2 = 4

3) the equation of the circle

(x-x0)² + (y-y0)²= r²

(x-7)² + (y+1)² = 4²=16