At a pressure 41 kPa, the gas in a cylinder has a volume of 16 liters. Assuming temperature remains the same, if the volume of t

Question

Gelneren [198K]

4 years ago

6

At a pressure 41 kPa, the gas in a cylinder has a volume of 16 liters. Assuming temperature remains the same, if the volume of t

he gas is decreased to 4 liters, what is the new pressure

Mathematics

1 answer:

DiKsa [7] · Answer 1 · 2021-11-28T01:12:29+03:00

DiKsa [7]4 years ago

6 0

If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes
P1V1 = P2V2 --> (41)(16) = P2 (4)
--> P2 (4) = 656
P2 = 656/4 = 164 kPa