7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
Start with the point-slope form: 
.
Then you substitue in the slope and coordinates from the point:
You don't do a lot of clean up to the form, with the exception of turning "minus negative 7" into "plus 7".
Thar be yer answer!
Answer:
I got (1,2).
Step-by-step explanation:
Process of elimination:
Multiply the second equation by 3 to get same terms, subtract and solve for Y to get 2.
Plug 2 into second equation for Y to get x=1
(1,2)
Answer: sorry i cant read it its to small
Step-by-step explanation:
Answer: The length is 20.
Step-by-step explanation:
If UW is the line segment, then the length of VW and UV has to equal to the length of UW
VW = 6
UV = 14
6 + 14 = 20
