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Gelneren [198K]
4 years ago
6

At a pressure 41 kPa, the gas in a cylinder has a volume of 16 liters. Assuming temperature remains the same, if the volume of t

he gas is decreased to 4 liters, what is the new pressure
Mathematics
1 answer:
DiKsa [7]4 years ago
6 0
If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes
P1V1 = P2V2 --> (41)(16) = P2 (4)
--> P2 (4) = 656
P2 = 656/4 = 164 kPa
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Which transformation(s) of circle C prove that circle A is similar to circle C ?
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3 years ago
Plz help i will give brainliest
djverab [1.8K]

Answer:

1. y=\frac{2}{3}x-2

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Step-by-step explanation:

all you are doing is solving for "y"

8 0
3 years ago
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At an ice cream store, a family ordered 1 banana split and 2 hot fudge sundaes, paying a total of $11 for their order. The next
Vladimir [108]

Answer:

$5 and $3

Step-by-step explanation:

Cost of banana split = b

Cost of hot fudge sundae = s

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<u>From the first equation we get: </u>

  • b = 11 - 2s

<u>Replacing in the second equation:</u>

  • 4(11 - 2s) + 3s = 29
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Then

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So banana split costs $5 and hot fudge sundae costs $3

8 0
3 years ago
The median of a data set 8, 21, 17, and 13 is 15. If 17 is changed to 18, what will be the new median? a. 15.5 c. 50 b. 17.5 d.
lubasha [3.4K]

Answer:

Option A) 15.5 is correct

The new median for the new data set is 15.5

Step-by-step explanation:

Given data set is 8,21,17,13

To find the median :

First order the given set of data into least to greatest

The ordered set is 8,13,17,21

Since the given set of data is even

We can take midvalues of data in the set

Median is the mean of two middle values in the data set

Median=\frac{13+17}{2}

=\frac{30}{2}

=15

Therefore Median=15 ( given )

Given that if 17 is changed to 18 then the given set of data  8,21,17,13 is changed into new set  8,21,18,13

To find the median :

First order the new set of data into least to greatest

The ordered set is 8,13,18,21

Since the given set of data is even

We can take two midvalues of new data in the set

Median is the mean of two middle values in the data set

Median=\frac{13+18}{2}

=\frac{31}{2}

=15.5

Therefore New Median=15.5

Therefore option A) 15.5 is correct

The new median for the new data set is 15.5

5 0
3 years ago
Help me simplify this, please!!
OlgaM077 [116]
- \sqrt[3]{2 x^{4} y^{2}  } *3 \sqrt[3]{20 x^{5}y } =-3  \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} =  \\ \\ =-3 \sqrt[3]{40 x^{9}  y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9}  y^{3}  } = \\  \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} }  \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}
Answer: B.
6 0
3 years ago
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