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NemiM [27]
3 years ago
5

If the plasma membrane wasn’t selectively permeable, what would happen to your cells when you took a shower? How would this affe

ct you?
Biology
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

i would let youre blood cells be <u>clean</u>

<h3>answer2</h3>

it does noting to effect you

<h3>hear me out</h3>

pls give me brainliest answer pls

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The most permeable capillaries, which contain fenestrations and large intercellular clefts, are called __________.
mote1985 [20]

Answer: Sinusoid capillaries

hope this helps!

5 0
2 years ago
In pea plants, purple flower color, C, is dominant to white flower color, c. The table shows the frequencies of the dominant and
GuDViN [60]

Answer:

Generation 1: p= 0.60 q= 0.40

Explanation:

Due to technical problems, you will find the complete answer and explanation in the attached file

Download pdf
5 0
3 years ago
What color(s)of light will drive photosynthesis by green plan most efficiently?
Anestetic [448]
<h3>C.Green only</h3>

At low light levels, green leaves are most efficient at photosynthesis. But well yeah, in sunny days, red light will work the same as green light

5 0
3 years ago
What is the meaning of life and death? will give brainliest to best answer.
4vir4ik [10]
Life and death are complex things. Life is the existence of something and death is the end. They go hand in hand. Without one you cannot have the other. To live means to die and to die means you have lived.
Hopes this helps. Add a comment if not and I will try to assist.
3 0
3 years ago
Read 2 more answers
A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
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