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Anastaziya [24]

2 years ago

13

There are 300 men and women at an afterschool meeting. 3/5 of the people are women. How many women are at the meeting? How many

men?

2 answers:

Alex Ar [27]2 years ago

8 0

Answer:

Well as a fraction it would be 2/5, if you would like it as a number you divide 300 by 3/5 and use the leftovers.

lora16 [44]2 years ago

8 0

300 divided by 5=60 and then multiply by 3

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Which list orders –3, 2, 5, –1 from least to greatest?

Allushta [10]

Answer:

so all the - 3's, all the -1's then all the 2's 3's then the 5's fro the greatets

Step-by-step explanation:

7 0

2 years ago

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Suppose a bus arrives at a bus stop every 35 minutes

Ratling [72]

Answer:

3/7

Step-by-step explanation:

The probability of at least is 1 - the probability of at most

P(at least x) = 1 - P(at most x)

The given is:

1. A bus arrives at a bus stop every 35 minutes

2. You arrive at the bus stop at a random time

3. You will have to wait at least 20 minutes for the bus

∵ The bus arrives at a bus stop every 35 minutes

∵ You arrive at the bus stop at a random time

∵ You will wait at most for 20 minutes for the bus

∴ P(at most 20 minutes) =

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∴ P(at least 20 minutes) = 1 -

∴ P(at least 20 minutes) =

- Simplify the fraction by divide up and down by 5 and you will get your answer!

please mark me brainliest!

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2 years ago

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Gelneren [198K]

Answer:

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6 0

1 year ago

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Help me pls this is math and im so confused

EleoNora [17]

9.08+x=25.08
-9.08 -9.08
x=16
3/4x=12
x4/3 x4/3
x=16

4.5x=72
/4.5 /4.5
x=16

Both

8 0

2 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

2 years ago