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tekilochka [14]
3 years ago
12

Kaleb’s gross semimonthly pay is $1670. To maintain his current lifestyle, how much should he save up by the time he retires? $1

,128,920 $961,920 $434,200 $400,800
Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

The correct answer is $400,800

Step-by-step explanation:

I just took the test and this is the correct answer.

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Solve this equation<br> y= 2x<br> x= -y + 6
zubka84 [21]

The solution is x = 2 and y = 4

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = 2x -------- eqn 1

x = -y + 6 ----------- eqn 2

We can solve the system of equations by substitution method

<em><u>Substitute eqn 1 in eqn 2</u></em>

x = -2x + 6

Move the variables to one side and constants to other side

x + 2x = 6

3x = 6

Divide both sides of equation by 3

x = 2

<em><u>Substitute x = 2 in eqn 1</u></em>

y = 2(2)

y = 4

Thus the solution is x = 2 and y = 4

6 0
4 years ago
Write a linear factorization of the function.
Dafna11 [192]

Answer:

C

Step-by-step explanation:

I'm pretty sure, good luck

5 0
4 years ago
What is the mode? (math)​
Serggg [28]
The mode is the value that appears more frequently. In this case, the mode is number 1.
5 0
3 years ago
PLEASE HELP I GIVE THANKS
My name is Ann [436]
For #1 is <em>A </em>because the -5\12 is greater than -2\5
For #2 is <em>C </em>because A is the same as the question and B,D ARE WRONG.
1:- A

2:-C
I HOPE THIS WOULD HELP YOU  THANK YOU
5 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
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