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3 years ago

7

I turned it in and it says we got one wrong(out of those blanks). I've checked over it several times but I can't figure out whic

h one. Could you guys help me figure out which one and what is the answer?

1 answer:

Colt1911 [192]3 years ago

8 0

Answer:

Try as percentages so

7) 37.5%

8) 50%

9) 12.5%

10) 62.5%

11) 87.5%

12) 50%

13) 62.5%

14) 37.5%

15) 100%

Step-by-step explanation:

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Solve for t. You must write your answer in fully simplified form. <br><br> −19=7t

nikitadnepr [17]

Answer:

t=-19/7

Step-by-step explanation:

you need to isolate for t which means you need to get t all alone on one side of the equation. Do do that you can divide both sides by 7. This gives you -19/7=7t/7

we know that anything divided by itself is 1 so we get -19/7=t

This is the simplest for because 19 and 7 are both prime numbers, so you can't simplify them.

7 0

2 years ago

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convert the linear equation 3x-2y=5 to point slope form. use the point with an x-coordinate equal to 1

Mademuasel [1]

When x = 1, y = (5 - 3) / -2 = -1 , let x1 = 1 and y1 = -1
2y = 3x - 5
so slope = 3/2

y - y1 = m(x - x1)

y -(-1) = (3/2)(x - 1)

y + 1 = 3/2 ( x - 1) <----- answer

6 0

3 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

3 years ago

if the probability of picking a pink jelly bean out of a bag is 4/15, what is the probability of not picking a pink jelly bean

KiRa [710]

Answer:

The probability of not picking a pink jelly bean: 11/15

Step-by-step explanation:

As we know that the maximum value of the probability of an event would always be 1.

The reason is that '1' is certain that something would happen.

Given that the probability of picking a pink jelly bean out of a bag is 4/15.

Thus, the probability of not picking a pink jelly bean can be calculated by subtracting 4/15 from the maximum probability '1'.

i.e.

Probability of not picking a pink jelly bean = max probability - 4/15

= 1 - 4/15

= 11/15

Therefore, the probability of not picking a pink jelly bean: 11/15

5 0

3 years ago

The equation of line k is y=

Nina [5.8K]

Answer:

Neither parallel nor perpendicular

Step-by-step explanation:

I'm assuming you meant line k is y = 3x -2. If not, this is wrong.

For this, you need to put both lines in point-slope form, or the form that line k is already in. This means you only need to convert line m.

-2r + 6v = 18

6v = 2r + 18

v = 2/6r + 18/6

v = 1/3r + 3

Now you can answer the question.

To be parallel, lines must have the same slope (but a different y-intercept). 3 and 1/3 are not the same, so the lines are not parallel.

To be perpendicular, one line must have the opposite reciprocal (fraction flipped and + goes to - or - to +) of the other. While 3 is the reciprocal of 1/3, they are both positive, so they are not perpendicular.

To be the same line, the equations must be absolutely identical, which they aren't.

This leaves the last option: neither.

Let me know if you need a more in-depth explanation of anything here! I'm happy to help!

3 0

3 years ago

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