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3 years ago

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Rectangle ABCD with length 24 feet and width 20 feet is dilated by a scale factor of 4/3. What is the area of rectangle A'B'C'D'

?

1 answer:

Natasha_Volkova [10]3 years ago

6 0

multiply the length and with by the scale factor:

24 x 4/3 = 32 feet

20 x 4/3 = 26 2/3 feet

Area is length x width:

32 x 26 2/3 = 853 1/3 square feet.

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Step-by-step explanation:

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Point c is the center of dilation. line segment b a is dilated to create line segment b prime a prime. the length of c a is 4. t

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The scale factor of the dilation of line segment ba for which the center of dilation is C, is 5.

<h3>What is the dilation of the figure?</h3>

Dilation of a figure, means the transformation of the figure. The factor by which the given figure dilated, called the scale factor of dilation.

Point c is the center of dilation. Line segment BA is dilated to create line segment b prime, a prime. The image of the given problem is attached below. The length of CA is 4.

$CA=4$

The length of a prime is 16.

$AA'=16$

The new dimension will be,

$CA'=CA+AA'\\CA'=4+16\\CA'=20$

Now, the scale factor is the ratio of the new dimension to the original dimension. Thus, the scale factor of the dilation is,

$r=\dfrac{20}{4}\\r=5$

This will be the same for the line segment BA. Thus, the scale factor of the dilation of line segment ba for which the center of dilation is C, is 5.

Learn more about the dilation of the figure here;

brainly.com/question/3457976

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