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jeka57 [31]
3 years ago
10

Rectangle ABCD with length 24 feet and width 20 feet is dilated by a scale factor of 4/3. What is the area of rectangle A'B'C'D'

?​
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

multiply the length and with by the scale factor:

24 x 4/3 = 32 feet

20 x 4/3 = 26 2/3 feet

Area is length x width:

32 x 26 2/3 = 853 1/3 square feet.

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5 0
2 years ago
Angle c is inscribed in circle O. AB is a diameter of circle O. what is the radius of circle.​
Llana [10]

Answer:

The value of radius is 7.5 units

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{c}^{2}  =  {a}^{2}  +  {b}^{2}

Let a = 12 units,

Let b = 9 units,

Let c = hypo.,

{hypo.}^{2}  =  {12}^{2}  +  {9}^{2}

{hypo.}^{2}  = 225

hypo. =  \sqrt{225}

hypo. = 15 \:  \: units

We have found out that the hypotenuse of the triangle is the diameter of circle. So in order to find radius, you have to divide it by 2 :

radius = diameter \div 2

radius = 15 \div 2

radius = 7.5 \:  \: units

6 0
3 years ago
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Mkey [24]
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5 0
2 years ago
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daser333 [38]

y=(-2x)+5

Step-by-step explanation:

4 0
2 years ago
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