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3 years ago

10

Rectangle ABCD with length 24 feet and width 20 feet is dilated by a scale factor of 4/3. What is the area of rectangle A'B'C'D'

?

1 answer:

Natasha_Volkova [10]3 years ago

6 0

multiply the length and with by the scale factor:

24 x 4/3 = 32 feet

20 x 4/3 = 26 2/3 feet

Area is length x width:

32 x 26 2/3 = 853 1/3 square feet.

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$\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill$

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