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3 years ago

Sam kicks a soccer ball from the ground. The height of

Mathematics

1 answer:

Alexeev081 [22]3 years ago

8 0

Answer:

The ball will take 2.6 seconds to hit the ground again.

Step-by-step explanation:

Sam kicks a soccer ball from the ground. The height of the ball (in feet) can be modeled with the function, h(t) = −16t(t − 2.6), where t is the time in seconds after the ball is kicked.

So, the ball will be at ground when h = 0 = - 16t(t - 2.6)

⇒ t = 0 or t = 2.6.

Therefore, the ball will take 2.6 seconds to hit the ground again. (Answer)

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domain is x range is y

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3 years ago

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2 years ago

Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a

Arisa [49]

Answer:

<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>

Step-by-step explanation:

Let, the specific heat of the container is x calories/gram-degree C.

The container and water gains (18 - 15) = 3 degrees C.

Hence, the transfer of heat is $3(18.1\times1000\times1) + 3(3.77x\times1000)$ .

The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.

Hence, the transfer of heat is $144\times 1.45\times1000x$ .

As per the given conditions,

$3(18.1\times1000) + 3(3.77x\times1000) = 144\times1.45\times1000x\\54.3 + 11.31x = 208.8x\\197.49x = 54.3\\x = 0.274951$ .

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3 years ago

OC and OR are similar. Find the length of QP.

Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is $s = \frac{22 \pi}{9}$

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s, r and $\theta$ is

$arclength = 2\pi r \frac{\theta}{360}$

where,

s be the length of the arc

r be the radius

$\theta$ be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

$2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}$

or, $2r \frac{\theta}{360} = \frac{22}{9}$ [ eliminating $\theta$ from both side]

or, $\theta = \frac{(22)(360)}{(9)(2)(4)}$

or, $\theta = 110^\circ$

Again,

For circle R

Taking, r = 6 and $\theta = 110^\circ$ we get,

The length of arc QP is

$arc length = 2\pi (6)(\frac{110}{360} )$

or, $arclength = \frac{11 \pi}{3}$

Hence,

The length of QP is $\frac{11 \pi}{3}$ . Option C.

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3 years ago

Convert 86 degrees Fahrenheit to degrees celsius

dybincka [34]

86 degrees Fahrenheit is 30 degrees Celsius

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