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Ket [755]
2 years ago
12

Geraldine is an accrual basis taxpayer who has the following transactions during the current calendar tax year: Accrued business

income (except rent) $220,000 Accrued business expenses (except rent) 170,000 Rental income on a building leased for the next 6 months, received on December 1 21,000 Prepaid rent expense for 6 months, paid on December 1 9,000 Calculate Geraldine's net income from her business for the current year.
Mathematics
1 answer:
Artyom0805 [142]2 years ago
3 0

Answer:

Total: $69,500

Step-by-step explanation:

Income:

Other than rental: 220,000

Rental: 21,000

Expenses:

Other than rental: (170,000)

Rental (9,000/6): (1,500)

Total: $69,500

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Algebra 2B U2 L6 Function Operations practice 8-10
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Answer:

1) f(g(0)) = 0

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Step-by-step explanation:

Here, the given functions are:

g(x)  =  3 x +2 and f(x)=  (x-2)/3

1. Now, f(g(x))  =   f(3x+2)

Also,  f(3x+2) = (3x+2 -2) /3 = x

So, f(g(x)) = x

⇒ f(g(0)) = 0

2.  g(f(x))  = g((x-2)/3) = 3((x-2)/3) +2

or, g(f(x)) =   x

⇒  g(f(2)) =   3((2)-2/3) +2   = 2  

or, g(f(2)) = 2

3.  g(g(0)= g( 3 (0) +2)  = g(2)

Now, g(2)  = 3(2) +  2 = 6 +  2 = 8

or, g(g(0)) = 8

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3 years ago
Which of the following statements are true about the lengths of the trails? Check all that apply.
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In parallelogram ABCD,m
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2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
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4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

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