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denis-greek [22]
3 years ago
11

What is the solution to log 2 (2x^3 -8 )-2log 2 x=log 2x

Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

x=9

Step-by-step explanation:

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~Help me with this please! I will mark as BRANLIEST and if you answer correctly there would be a 55 point question for you!!!
4vir4ik [10]

Answer:

Simply here we use system of 2 equations.

Step-by-step explanation:

Let x be the cost of one small shirt and let y be that of one large shirt.

(4x +14y =210) (-3)

12x +11y =110

-12x - 42y= -630 note:cross 12x and - 12x

12x +11y =110

__________

-42y +11y = - 630 +110

-31y = -520

Y=520/31

Replace y in second equation:

12x +11y =110

12x +11(520/31) =110

12x +5720 =110

12x =110 - 5720/31

X= - 385/62

So one small shirt costs - 385/62 $

And a large one costs 520/31 $

Though I think there's something wrong in this problem since i verified my answer using calculator the same prices are obtained and as u see the cost of a small shirt is negative which is unbelievable.. So plz make sure from anyone else. I tried my best to help.

5 0
3 years ago
Please see attached. Please help me. Please answer a b and c
MariettaO [177]

Answer:

b) 25

c)14

Step-by-step explanation:

3 0
4 years ago
Find the square root of the fraction . 64/100
Artyom0805 [142]
It would be 8/10 because you just take the square root of the denominator and the numerator
3 0
4 years ago
Jack and Jim sign up with an online music store. Jack chooses 15 downloads for $19.75, and Jim chooses 40 downloads for $43.50.
lina2011 [118]
The answer would be A. <span>The registration fee is $5.50, and the cost per download is $0.95.</span>

Solution
Let x = registration fee
y = cost/downloads

Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50

Thus,
40y + x = 43.50
40y + <span>19.75 - 15y = 43.50
</span>25y = 23.75
y= 0.95

for x,
<span>x = 19.75 - 15y</span>
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
x = 5.5
3 0
4 years ago
17x - 7 = 5 + 13x<br> x=
Sphinxa [80]

Answer:

DeeDee jdjdjcj. ejfjcjcj jjdjejfj 3

6 0
3 years ago
Read 2 more answers
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