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Oxana [17]
3 years ago
12

Solve: 3/x-4 >0 x < 4 x > -4 x > 4 x < -4

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

x>4

Step-by-step explanation:

3/(x-4) >0

Divide each side by 3

3/(x-4) * 1/3 >0*1/3

1/(x-4) >0

We know if 1/(x-4) >0 then x-4 > 0

x-4>0

Add 4 to each side

x-4+4 >0+4

x>4

IgorLugansk [536]3 years ago
5 0

\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}

:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}

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3 years ago
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AysviL [449]

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<h3>Area and perimeter of rectangle</h3>

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