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1 year ago

11

Mathematics

1 answer:

Vladimir [108]1 year ago

4 0

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

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20 POINTS If the perimeter of a triangle is 14.4. What is the area?

sweet-ann [11.9K]

Answer:

A = 9.9648

Step-by-step explanation:

if the triangle is equilateral =>

P = 3L => L = 14.4/3 = 4.8

A = L²√3/4

= (4.8)²√3/4

= 23.04√3/4

= 5.76×1.73

= 9.9648

7 0

3 years ago

Help, please Jake has $100 of birthday money in his wallet. He spends $15 at Twistee Treat and $10 at Wawa. While walking home h

Alchen [17]

Answer:

The expression is $x=100-15-10+20-40+35$

Jake has in his wallet $\$90$

Step-by-step explanation:

Let

x-----> the money that Jake has in his wallet

we know that

The expression that represent the situation is equal to

1) Jake has $100 of birthday money in his wallet

so

$x=100$

2) He spends $15 at Twistee Treat and $10 at Wawa

so

$x=100-15-10$

3) He finds a $20 bill on the ground

so

$x=100-15-10+20$

3) His friend borrows $40 from Jake

so

$x=100-15-10+20-40$

4) At home, Jake mows the lawn and earns $35

so

$x=100-15-10+20-40+35$

$x=\$90$

5 0

3 years ago

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GarryVolchara [31]

Answer:

1.97 feet

HOPE THIS HELPS VOTE THIS BRAINLIEST

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

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o-na [289]

Answer:

AREA =18

Step-by-step explanation

think of a rectangle, 12 by 3 which is also 12*3

so you do 12*3=36

but since it is a triangle you have to divide it by 2

36/2=18

18

5 0

3 years ago

Read 2 more answers

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lukranit [14]

4!•3! = 144
you’re welcome :)

8 0

3 years ago