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lyudmila [28]
3 years ago
8

7x-4=5x+15 solve the following equation

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
Remember you can do anything to an equaiton as long as you do it to both sides


7x-4=5x+15
minus 5x both sides
2x-4=15
add 4 both sides
2x=19
divide by 2
x=19/2

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In triangle PQR, m angle R = 32, p = 21, and q = 21. what is side lenth r? explain each step
Karo-lina-s [1.5K]

Answer:

11.577 = r

Step-by-step explanation:

Comment

When you draw a sketch of this, <R is between p and q - - both of which are lines. The Cos law is the one you use.

Equation

r^2 = p^2 + q^2 - 2pq * Cos(R)

Givens

p = 21

q = 21

R = 32

r = ?

Solution

r^2 = 21^2 + 21^1 - 2*21*21 * Cos(32)     Substitute givens into the equation

r^2 = 441 +441 - 882 * 0.8480               Add the first two terms.

r^2 = 882 - 747.98                                 Multiply Cos(32)  by 2 * 21 * 21

r^2 = 134.02                                            Subtract 747.98 from 882

sqrt(r^2) = sqrt(134.02)                           Take the square root of both sides.

r = 11.577

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3 years ago
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