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3 years ago

9

How do you solve domain and range

1 answer:

elixir [45]3 years ago

4 0

Go to the x and y and find the numbers between them and mark them...tell me if this is confusing or not

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Mya told her friend, “If you increase my sisters age by 6, multiply that quantity by 12, and then subtract 4, you get 10. Write

Lostsunrise [7]

Answer: x+6(12-4) = 10

Step-by-step explanation:

7 0

2 years ago

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

vlabodo [156]

160/140 = x/56
cross multiply
(140)(x) = (160)(56)
140x = 8960
x = 8960/140
x = 64 lbs <== Vince's weight on the other planet

5 0

3 years ago

Read 2 more answers

Guys I need your help , what is - 16t2 + 64+ + 3?

bija089 [108]

Answer:

the answer is -32t + 67

Step-by-step explanation:

-16t2 +64 + 3

= -16t x 2 +64 +3

= -32t +67

3 0

3 years ago

Read 2 more answers

Find x. Leave answers in simplified radical form. (Step by step)

just olya [345]

Answer:

$\sf x = 4\sqrt{2}$

Given:

adjacent: 4 cm
hypotenuse: x cm
angle: 45°

<u>using cosine rule:</u>

$\sf cos(x) = \dfrac{adjacent}{hypotenuse}$

$\sf cos(45) = \dfrac{4}{x}$

$\sf x = \dfrac{4}{cos(45)}$

$\sf x = 4\sqrt{2}$

4 0

2 years ago

Read 2 more answers