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Degger [83]
2 years ago
6

What is the equation of a line that is parallel to the given line and passes through the point (-2,2)

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
3 0

The equation of the line will be y = \dfrac{1}{5}x + \dfrac{12}{5}

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

First, we need to find the equation of the line that is given:

We can use the formula,

m = \dfrac{y_1 - y_2}{x_1-x_2}

m=\dfrac{-3-(-4)}{0-(-5)}=\dfrac{1}{5}

So the equation for this line is  

y = (1/5) x - 3

This means that the equation for the line we are trying to find has a slope of as well

Let's put the points in the equation and try to find the y-intercept:

2 = \dfrac{1}{5} ( -2 ) + b

\dfrac{15}{5} = b

So the final equation for the line we are trying to find is y = \dfrac{1}{5}x + \dfrac{12}{5}

To know more about equations follow

brainly.com/question/2972832

#SPJ1

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Answer:

Length=10.5\ ft

Width=10.5\ ft

Area=110.25\ ft^{2}

Step-by-step explanation:

Let

x----> the length of the rectangular garden

y---> the width of the rectangular garden

we know that

The perimeter of the rectangle is equal to

P=2(x+y)

we have

P=42\ ft

so

42=2(x+y)

simplify

21=(x+y)

y=21-x------> equation A

Remember that the area of rectangle is equal to

A=xy ----> equation B

substitute equation A in equation B

A=x(21-x)

A=21x-x^{2}----> this is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex is the maximum area

The x-coordinate of the vertex is the length side of the rectangle that maximize the area

using a graphing tool

The vertex is the point (10.5,110.25)

see the attached figure

so

x=10.5\ ft

Find the value of y

y=21-10.5=10.5\ ft

The garden is a square

the area is equal to

A=(10.5)(10.5)=110.25\ ft^{2} ----> is equal to the y-coordinate of the vertex is correct

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