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2 years ago

What is the equation of a line that is parallel to the given line and passes through the point (-2,2)

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

3 0

The equation of the line will be y = $\dfrac{1}{5}x + \dfrac{12}{5}$

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

First, we need to find the equation of the line that is given:

We can use the formula,

$m = \dfrac{y_1 - y_2}{x_1-x_2}$

$m=\dfrac{-3-(-4)}{0-(-5)}=\dfrac{1}{5}$

So the equation for this line is

y = (1/5) x - 3

This means that the equation for the line we are trying to find has a slope of as well

Let's put the points in the equation and try to find the y-intercept:

2 = $\dfrac{1}{5}$ ( -2 ) + b

$\dfrac{15}{5} = b$

So the final equation for the line we are trying to find is y = $\dfrac{1}{5}x + \dfrac{12}{5}$

To know more about equations follow

brainly.com/question/2972832

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The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

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Step-by-step explanation:

GIVEN :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

TO FIND :

in the provided question we need to find :

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$\begin{gathered}\end{gathered}$

USING FORMULAS :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

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➛ Csa = Curved surface area
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➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

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Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$

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