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belka [17]
3 years ago
8

Someone can help me ASAPP??

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0

Answer: 23

Step-by-step explanation:

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Sam rotated parallelogram ABCD 90° clockwise around the origin. If angle A is 130° and angle B is 50°, what is the degree measur
fomenos
The degree measurement of angle A is already equal to 50 degrees.
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3 years ago
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2(3x+10)=6x+20 does this equation have one solution or many ? Explain why
mylen [45]

Answer:

2(3x+10) = 6x+20

6x+20 = 6x+20

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x = x

This has an infinite amount of solutions

Step-by-step explanation:

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Erica walked down a trail into a valley. V(d) models Erica's vertical distance from the top of the valley (in kilometers) after
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<u>THE ANSWER IS B.</u>

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After she had walked 2K along the trail, Erica's vertical distance from the top of the valley was equal to T kilometers.

I just checked it and this was the right answer.

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What is 365 divided by 20%
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3 years ago
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Suppose KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. Prove that A is equidistant from LM and KN.
Neporo4naja [7]

Answer:

This is proved by ASA congruent rule.

 Step-by-step explanation:

Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ

we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.

In ΔAPN and ΔAQL

∠PNA=∠ALQ    (∵alternate angles)  

AN=AL   (∵diagonals of parallelogram bisect each other)

∠PAN=∠LAQ      (∵vertically opposite angles)

∴ By ASA rule ΔAPN ≅ ΔAQL

Hence, by CPCT  i.e Corresponding parts of congruent triangles PA=AQ

Hence, A is equidistant from LM and KN.

7 0
3 years ago
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