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adell [148]
3 years ago
5

5. y = x + 2 solve by graphing, test your solutiony = 3x​

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

1

Step-by-step explanation:

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A box of popcorn weighs 15/16 pounds. The box contains 1/3 buttered popcorn and 2/3 cheesy popcorn. How much does the cheesy pop
ella [17]

we know that

To find the weight of the cheesy popcorn Multiply the total weight by the proportion of the cheesy popcorn

so

\frac{15}{16} *\frac{2}{3}=\frac{30}{48}=\frac{5}{8}\ pounds

therefore

<u>the answer is</u>

the weight of the cheesy popcorn is \frac{5}{8}\ pounds

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! I NEED HELP URGENTLY
kirill [66]

Answer:

You would click (1,-5)

Step-by-step explanation:

The absolute minimum is the lowest point of the graph.

In all graphs, if it says minimum, it almost certainly means that lowest point, and if there are more than one, you would simply click on those.

It does not matter how many points there are, only that they are the lowest.

Therefore, it would be 1,-5.

3 0
3 years ago
Read 2 more answers
7. A clothing salesman wants to earn $6,000 in May. He receives a base salary of $4,000 per month as well as 10%
olya-2409 [2.1K]

Answer:

No of clothes to be sold to gain $6000=20,000

Given:

Base salary = $4000

Rate of Commission = 10%

Amount salesman wants to earn in May = $6000

To find:

How much clothing units needed to be sold in order gain $6000 in may

<u>Step by Step Explanation: </u>

Solution;

According to the formula;

\text { Amount earned through commission }=\text { Total amount earned - Base salary }

=6000 - 4000 = 2000

Also we know,  

\text { Amount earned through commission }=\text { Rate of Commission } \times \text { clothing to be sold }

Let the commission amount be x

10 \% \times x=2000

10 / 100 \times x=2000

0.1 \times x=2000

x=20,000 \div 0.1

x=20,000

Result:

Hence, the clothing to be sold in order to earn $6000 is 20,000 units.

4 0
4 years ago
Simplify. Write the expression using only positive exponents. 6y^−4
Alexxx [7]
6/y^4 this is the answer
5 0
4 years ago
Read 2 more answers
How many trucks carried only late variety?
murzikaleks [220]

9514 1404 393

Answer:

  • late only: 15
  • extra-late only: 24
  • one type: 43
  • total trucks: 105

Step-by-step explanation:

It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.

For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.

Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.

__

a) 15 trucks carried only late

b) 24 trucks carried only extra late

c) 4+15+24 = 43 trucks carried only one type

d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out

8 0
3 years ago
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