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3 years ago

Question 15(Multiple Choice Worth 5 points)

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

Update: The answer was correct I took the test

Answer:

I believe the answer is

Rational negative 4 over 5., 2.5, 0 point 4 bar., square root of 16.

Irrational square root of 2.

Step-by-step explanation:

Because -4/5, 2.5, square root of 16 are all rational.

and square root of 2 is irrational, I will say there is a promblem with the answer because of 0 point 4 bar is irrational i believe but it's in the rational spot.

Again I am not sure this answer is totally correct but i will updated the answer when I am done with the test.

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3. Gas is $2.09 per gallon at the gas station. If

balu736 [363]

Answer:

33.44/2.09= 16 gallons

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3 years ago

Read 2 more answers

Brainliest answer!

pickupchik [31]

She added the check fee instead of subtracting it

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3 years ago

HELP 5 MINS FOR QUIZ.<br><br> What is the location of point B? (-2,9) (2,-9) (9, 2) (9,-2)

Pepsi [2]

Answer:

(9,-2)

Step-by-step explanation:

9 is on x and y is -2

(x,y) is the rule so here ya go hope it helps :)

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3 years ago

This is super easy ik it its just my brain hurts, will give branliest

natka813 [3]

.5x=10+.25x
.25x=10
x=40
When you buy 40 songs
The cost equals 20$

3 0

3 years ago

Suppose that 50% of all babies born in a particular hospital are boys. If 6 babies born in the hospital are randomly selected, w

WINSTONCH [101]

Using the binomial distribution, it is found that there is a 0.3438 = 34.38% probability that fewer than 3 of them are boys.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

n = 6, p = 0.5.

The probability that fewer than 3 of them are boys is given by:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.5)^{0}.(0.5)^{6} = 0.0156$

$P(X = 1) = C_{6,1}.(0.5)^{1}.(0.5)^{5} = 0.0938$

$P(X = 2) = C_{6,2}.(0.5)^{2}.(0.5)^{4} = 0.2344$

Then:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0156 + 0.0938 + 0.2344 = 0.3438$

0.3438 = 34.38% probability that fewer than 3 of them are boys.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0

2 years ago