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FinnZ [79.3K]
3 years ago
12

Calculate the area of the irregular polygon shown below:

Mathematics
2 answers:
zaharov [31]3 years ago
5 0

Answer:

The area of the irregular polygon is 24 square inches

Step-by-step explanation:

we know that

The area of the irregular polygon shown, is equal to the area of the whole rectangle minus the two empty rectangular spaces

so

A=(7*12)-2*(6*5)\\ \\A=84-60\\ \\A=24\ in^{2}

xz_007 [3.2K]3 years ago
3 0
24 square inches. do the area of the whole rectangle (7x12) and subtract the two little rectangles (5X6) x 2= 60 so 84-60=24
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3 years ago
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MatroZZZ [7]
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3 years ago
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den301095 [7]

Answer:

Part A)

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y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

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The point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11)  in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Thus, the equation in the point-slope form is:

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Read 2 more answers
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