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Svet_ta [14]
3 years ago
15

temperature in Alexandria Kentucky from 45 degrees to 10 degrees in 5 hours what is the average change in temperature per hour

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0
So the difference between 45 and 10 is..
 35 (omygad)

You have to divide 35/5 to get the average drop in the temperature PER HOUR, meaning 7 degrees per hour.
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Solve the equation 40 = -10(y+0.3). what does the y equal​
alexdok [17]

Answer:

y = -4.3

Step-by-step explanation:

40 = -10(y + 0.3) <em>{Step 1: Use the distributive property to multiply -10 by y + 0.3}</em>

40 = -10y + -10(0.3)

40 = -10y - 3 <em>{Step 2: Add 3 to both sides.}</em>

40 + 3 = -10y

43 = -10y <em>{Step 3: Divide both sides by -10}</em>

43/-10 = y

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y equals -4.3.

4 0
3 years ago
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What are the roots of the polynomial equation x3-7x=6x-12?
Ilia_Sergeevich [38]
This is not a polynomial equation unless one of those is squared.  As it stands x=-.833.  If you can tell me which is squared I can help solve the polynomial.

Ok, that is usually notated as x^3 to be clear.   I'll solve it now.

x^3-13x-12=0

Then use factor theorum to solve x^3-13x-12/x+1 =0
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x=-1

Then you have x^2-x-12 now you complete the square.

Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:

The x-term coefficient = −1

The half of the x-term coefficient = −1/2

After squaring we have (−1/2)2=1/4

When we add 1/4 to both sides we have:

x2−x+1/4=12+1/4

STEP 3: Simplify right side

x2−x+1/4=49/4

STEP 4: Write the perfect square on the left.

<span>(x−1/2)2=<span>49/4
</span></span>

STEP 5: Take the square root of both sides.

x−1/2=±√49/4

STEP 6: Solve for x.

<span>x=1/2±</span>√49/4

that is,

<span>x1=−3</span>

<span>x2=4</span>

<span>and the one from before </span>

<span>x=-1</span>

7 0
4 years ago
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Answer:

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1-2k=-3k

1-2k+2k=-3k+2k

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1/-1=-1k/-1

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3 0
3 years ago
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lisov135 [29]
The answer is A=64 but I’m not pretty sure
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Angelina_Jolie [31]

Step-by-step explanation:

By using Ms Excel you should do this problem.

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