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3 years ago

What is the volume of 17.6

Mathematics

2 answers:

marta [7]3 years ago

8 0

In what?
The volume is 44%

creativ13 [48]3 years ago

4 0

The volume is 44%. Hope this helps

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HELP ASAP I’ll mark you as brainlister

noname [10]

Answer:The answer is 3.2 yards

Step-by-step explanation:

7 0

3 years ago

An insurance company has a merit rating system for customers who have not filed a claim in the previous year. For each year that

Valentin [98]

Answer:

B. Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

Step-by-step explanation:

The options above are examples of recurrence relations where the present state Fₙ₊₁ is dependent on the previous state Fₙ.

For each year that a customer does not file a claim, their rate is reduced by 15%

Fₙ-(15% of Fₙ)= Fₙ-0.15Fₙ

A credit of $5 is also awarded, therefore:

Fₙ - 0.15Fₙ + $5

Therefore If a customer did not file a claim in the nth year, the customer's rate in the (n + 1)th year as a function of their rate in the nth year is given by:

Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

4 0

3 years ago

Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the

Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is F

$t = 1.17$

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the test statistics is outside the rejection region , we fail to reject the null hypothesis ,There is no statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

The claim is $\mu = 0$

Hence

The null hypothesis is $H_o : \mu = 0$

The alternative is $H_a : \mu \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }$

=> $t = \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }$

=> $t = 1.17$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

$df = 9 - 1$

$df = 8$

From the student t-distribution table the critical value of $\alpha$ at a degree of freedom of 8 is

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the $t_ {\alpha , df}$ is outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim