A line has a slope of 1 the points are (8,-5) and (g,-6) solve for g

A student used the complex fraction

34kurt

Answer:1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help...its for Delta math. will mark brainliest and I will be ur friend♥

REY [17]

The exponential functions change is represented by decay and the percentage rate of decrease is 1.00619%.

Step-by-step explanation:

Step 1:

To determine if the function represents growth or decay, we substitute values to x.

If the values increase with an increase of x, it represents growth.

If the values decrease with an increase of x, it represents decay.

Step 2:

If $x= 10,$ $y = 1,300 (\frac{1}{2})^{\frac{10}{69} } = 1,300 (0.9044) = 1,175.72.$

If $x=11,$ $y = 1,300 (\frac{1}{2})^{\frac{11}{69} } = 1,300 (0.8953) = 1,163.89.$

So as x increases the value of y decreases, so it represents decay.

Step 3:

The percentage rate of change is determined by dividing the difference of two consecutive values by the first value.

The percentage rate of change $= \frac{y(x=11) - y(x=10)}{y(x=10)}.$

Substituting the values, we get

The percentage rate of change $=\frac{1,175.72-1,163.89}{1,175.72}(100) = 1.00619\%$ .

As the values of y decrease with an increase in x, it is the percent decrease per unit.

5 0

4 years ago

Read 2 more answers

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

Which equation could be used to find the height of the flagpole?

Andrew [12]

Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.

Let x be the height of the flagpole, then

$\sin50^o= \frac{x}{5}$

Therefore, the equation that could be used to find the height of the flagpole is
x/5 = sin 50

6 0

3 years ago

Find the area of the polygon with vertices (1, 2) (1, -5) (5, -5) (5,2)

Svetradugi [14.3K]

Answer:

28 square units

Step-by-step explanation:

These vertices are written in the form of their x and y coordinates. Let

A=(1,2) ; B =(1,-5) ; C =(5, -5) ; D=(5,2)

The x points are 1, 1, 5, 5

The y points are 2,-5, -5, 2

The x extremes range from 1 to 5. The length in-between is 5-1 = 4

The y extremes range from -5 to 2. The length in-between is 2-(-5) = 7

Area of the polygon enclosed by the coordinates

= 4 x 7 = 28 square units

5 0

3 years ago