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horrorfan [7]
3 years ago
14

Keelin wants to find the value of t in the equation 1/3 (15t-30) =50 Her work is shown below.

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

distrubutive

Step-by-step explanation:

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Cole ride his bike for 45 miles at a rate if 15 miles per hour. How long did it take him to ride in 40 miles? PLEASE HELP
tatiyna
15x=45
45/15 =3
X=3
45 miles in 3 hours

How long did it take for 40 miles?

15x=40
40/15 = 2.6666667

15 x 2= 30
15 x 2.5 = 37.5
15 x 2.6 = 39
15 x 2.7 = 40.5
1 hour equals 60 mins

Answer:
It took Cole about 2 hours and 6 mins to ride 40 miles.
5 0
3 years ago
Could someone please answer this question!!?
telo118 [61]
The answer is 14
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4 0
3 years ago
What is the density of the oak board
Andrei [34K]
We need more info or a pic
8 0
2 years ago
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Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten. The rest were either ripe or unripe. There were 18 more ripe oranges
Natalka [10]

Answer:

13:8:7

Step-by-step explanation:

84 - 24 = 60

60 oranges were either ripe or unripe.

18 more ripe oranges than unripe oranges.

x + 18 = ripe oranges

x = unripe oranges

x + 18 + x = 60

2x + 18 = 60

2x = 42

x = 21

21 are unripe oranges

21 + 18 = 39

39 oranges are ripe.

Ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.

39:24:21

13:8:7

4 0
4 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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