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4 years ago

How to simplify all this numbers to make one equation?

Mathematics

2 answers:

Marat540 [252]4 years ago

6 0

$6-(x+2)-4x=6-x-2-4x=-5x+4$

worty [1.4K]4 years ago

5 0

6-(x+2)-4x You must first multiply all terms in the parentheses by -1

6-x-2-4x, then you must combine like terms

(-x-4x)+(6-2)

-5x+4

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2 years ago

Read 2 more answers

300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A

Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle + The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0

3 years ago

A newly launched clothing line is rapidly increasing in popularity. Every month 20% more items of clothing are sold. If 70,800 i

prohojiy [21]

Answer:

<u>212,400 items</u> were sold in 10 months.

Step-by-step explanation:

Given:

Items sold this month = 70,800

Percent Increase in every month = 20%

We need to find number of items sold in coming 10 months.

Solution:

First we will find number of items increase in each month.

number of items increase in each month can be calculated by Percent Increase in every month multiplied by Items sold this month and the divided by 100.

number of items increase in each month = $\frac{20}{100} \times 70800 = 14,160$

Now we will find number of item sold in 10 months.

number of item sold in 10 months is equal to sum of Items sold this month and number of items increase in each month multiplied by 10.

framing in equation form we get;

number of item sold in 10 months = $70800+10\times 14160 = 212,400$

Hence <u>212,400 items</u> were sold in 10 months.

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3 years ago