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umka2103 [35]
3 years ago
5

The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
L=w+2 and 2w+2l=44

substitute equation for length in perimeter equation

2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10

substitute width into length equation to get length

l=10+2
l=12

a=lw
a=12*10
a=120 cm^2
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A suitcase measures 24 inches long and the diagonal is 30 inches long. How much material is needed to cover one side of the suit
azamat

Answer:

I believe you're supposed to solve for the other missing side. If you know a side (a) and the diagonal or also known as the hypotenuse (c), you will be able to solve for the other side using the Pythagorean theorem.

Step-by-step explanation:

a^2+b^2=c^2 Substitute the values for a and c

24^2+b^2=30^2 Solve for the powers

576+b^2=900 Subtract 576 from both sides

b^2=324 Solve for the root of 324

18=b

You would need 18 inches of material to cover one side of the suitcase.

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3 years ago
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LekaFEV [45]

Answer:

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7 0
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Expand and simplify 4(x-2)+7(x-1)​
Zolol [24]

Answer:

11x-15

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Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 ).
Zielflug [23.3K]

Answer:

y = 1/2x - 6

Step-by-step explanation:

y2 - y1 / x2 - x1

-2 - (-5) / 8 - 2

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3 years ago
Do this worksheets if someone do I will make him or her brainly if correct.
marusya05 [52]
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3 years ago
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