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umka2103 [35]
3 years ago
5

The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
L=w+2 and 2w+2l=44

substitute equation for length in perimeter equation

2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10

substitute width into length equation to get length

l=10+2
l=12

a=lw
a=12*10
a=120 cm^2
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4 0
2 years ago
Brainliest if corerct
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Step-by-step explanation:

2x + 2  = 3x - 52

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5.<br>Find the sum of all two - digit natural numbers which are divisible by 3.​
kykrilka [37]

Answer:

1665

Step-by-step explanation:

This is AP, where:

  • First term is: 12= 3*4
  • Last term is: 99= 3*33
  • Common difference is: 3
  • Number of terms is: 33- 3= 30 (because the 4th term is included)
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The sum of all two - digit natural numbers which are divisible by 3 is 1665

3 0
3 years ago
According to the text, the specific things that people want in life are called
Oksi-84 [34.3K]

Answer:

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4 0
3 years ago
Answer this question​
Stells [14]

Answer:

\huge\boxed{width=12cm}

Step-by-step explanation:

l-length\\w-width\\P-perimeter

The formula of perimeter of the rectangle:

P=2l+2w=2(l+w)

Substitute:

l=6w\\\\P=168cm

168=2(6w+w)\\168=2(7w)\\168=14w\qquad|\text{divide both sides by 14}\\\\\dfrac{168}{14}=\dfrac{14w}{14}\\\\12=w\Rightarrow w=12(cm)

3 0
3 years ago
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