The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area
1 answer:
L=w+2 and 2w+2l=44
substitute equation for length in perimeter equation
2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10
substitute width into length equation to get length
l=10+2
l=12
a=lw
a=12*10
a=120 cm^2
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It's D because 140÷3.50 is 40
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The answer is C (10.89 m)
x * 9 = 98 m²
x = 98 ÷ 9
x = 10.888888 or 10.89 m
