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2 years ago

The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area

1 answer:

Natasha2012 [34]2 years ago

7 0

L=w+2 and 2w+2l=44

substitute equation for length in perimeter equation

2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10

substitute width into length equation to get length

l=10+2
l=12

a=lw
a=12*10
a=120 cm^2

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Mumz [18]

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Step-by-step explanation:

Given

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3 years ago

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2 years ago

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seropon [69]

Answer:

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Step-by-step explanation:

1) find the distance of the points

$\sqrt{(x2-x1)^2 + (y2 -y1)^2}$

AB = $\sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}$

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