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2 years ago

50 points !!! Will also mark brainliest Show work for brainliest

Mathematics

2 answers:

Marina86 [1]2 years ago

5 0

If the discrimination is >0 there are 2 solution, <0 no solotuions or =0 1 solution.

a^2 + 3a = 7

Set the equation equal to 0 by subtracting 7 from both sides:

a^2 + 3a -7 = 0

A = 1, b = 3 c = -7

Discriminate = b^2 -4ac

3^2- 4(1)(-7) = 37

The discriminate = 37

There are 2 solutuons

Arlecino [84]2 years ago

3 0

Answer:

a2-3a-7=0

Step-by-step explanation:

hope this helps

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A candidate for one of Ohio's two U.S. Senate seats wishes to compare her support among registered voters in the northern half o

Radda [10]

Answer:

$(0.531-0.45) - 1.96 \sqrt{\frac{0.531(1-0.531)}{2000} +\frac{0.45(1-0.45)}{2000}}=0.050$

$(0.531-0.45) + 1.96 \sqrt{\frac{0.531(1-0.531)}{2000} +\frac{0.45(1-0.45)}{2000}}=0.112$

And the best option for this case would be:

A. 0.050 to 0.112.

Step-by-step explanation:

Data given

$p_A$ represent the real population proportion of who support the cnadite for the northern half state

$\hat p_A =\frac{1062}{2000}=0.531$ represent the estimated proportion of who support the candidate for the northern half state

$n_A=2000$ is the sample size required the northern half state

$p_B$ represent the real population proportion of who support the candidate for the southern half state

$\hat p_B =\frac{900}{2000}=0.45$ represent the estimated proportion of people who support the candidate for the southern half state

$n_B=2000$ is the sample size for the northern half state

$z$ represent the critical value

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile in the normal standard distribution and we got.

$z_{\alpha/2}=1.96$

Replacing into the formula we got:

$(0.531-0.45) - 1.96 \sqrt{\frac{0.531(1-0.531)}{2000} +\frac{0.45(1-0.45)}{2000}}=0.050$

$(0.531-0.45) + 1.96 \sqrt{\frac{0.531(1-0.531)}{2000} +\frac{0.45(1-0.45)}{2000}}=0.112$

And the best option for this case would be:

A. 0.050 to 0.112.

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3 years ago

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Answer:

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I GOT IT CORRECT

Step-by-step explanation:

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Answer:

$\sf adjacent = 4.5 \ ft$

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