Answer:
b
Step-by-step explanation:
only b is true
Given that,
An equation : -9c² +2c +3 = 0
To find,
Find the value of x.
Solution,
We have, -9c² +2c +3 = 0
We can solve it using the formula as follows :
![x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Here, a = -9, b = 2 and c =3
Put the values,
![c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69](https://tex.z-dn.net/?f=c%3D%5Cdfrac%7B-2%5Cpm%20%5Csqrt%7B%282%29%5E2-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%5C%5C%5C%5Cc%3D%5Cdfrac%7B-2%2B%5Csqrt%7B%282%29%5E%7B2%7D-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%2C%20%5Cdfrac%7B-2-%5Csqrt%7B%282%29%5E%7B2%7D-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%5C%5C%5C%5Cc%3D-0.47%2C%200.69)
So, the solution are -0.47 and 0.69.
Answer:
FOR H_2
![1 \mu mol/L = 2\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%202%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
Step-by-step explanation:
Given data:
concentration ![0.6 \mu mol/L](https://tex.z-dn.net/?f=0.6%20%5Cmu%20mol%2FL)
WE KNOW THAT
![ONE\ \mu = 10^{-6}](https://tex.z-dn.net/?f=ONE%5C%20%20%5Cmu%20%3D%2010%5E%7B-6%7D)
therefore
![1 \mu mol/L = 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%2010%5E%7B-6%7D%20mol%2FL)
Now for conversion of mol to gram need the molar mass of element in which particular value convert to.
let us take ![H_2](https://tex.z-dn.net/?f=H_2)
we know that molar mass of
is 2 gram
therefore
![1 \mu mol/L = 2\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%202%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
let take other example, for ![O_2](https://tex.z-dn.net/?f=O_2)
we know that molar mass of O_2 is 32 gram
therefore
![1 \mu mol/L = 32\times 10^{-6} mol/L](https://tex.z-dn.net/?f=1%20%5Cmu%20mol%2FL%20%3D%2032%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
Gradient = 5
9 = 5 + c
C = 4
Answer:
Y=5x+4