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Anon25 [30]
4 years ago
13

Explain in words how to find the product of -4(-1.5) using a number line. where do you end up?

Mathematics
1 answer:
Inessa [10]4 years ago
6 0
You end up at positive six 
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The composition Do,0.75(x,y). Do,2(x,y) is applied to LMN to create L”M”N”
Vera_Pavlovna [14]

Transformation involves changing the position and size of a shape.

The true statements are:

  • ∠m≅∠m'
  • Δlmn≅Δl'm'n'
  • The coordinates of n" are .N''(3,-1.5)

The complete question is as follows:-

The composition do,0.75(x,y) ∘ do,2(x,y) is applied to △lmn to create △l''m''n''. which statements must be true regarding the two triangles? check all that apply. ∠m ≅ ∠m'' △lmn ~ △l''m''n'' △lmn ≅ △l''m''n'' the coordinates of vertex l'' are (-3, 1.5). the coordinates of vertex n'' are (3, -1.5). the coordinates of vertex m'' are (1.5, -1.5).

<h3>What is translation?</h3>

The process of changing the location of the image on the coordinate system will be known as the translation.

The coordinates of the triangle are:

L =(-1,2)

M = (-1,-1)

N = ( 2,-1)

The transformation rule is given as:

do 0.75 (x,y) 2 (x,y)

The transformation rule is a dilation by a factor of 0.75, and then a factor of 2.

Uniform dilation changes the size of a shape, but the angles remain unchanged. This means that:

∠l≅∠l''

∠m≅∠m''

∠n≅∠n''

Δlmn⇒Δl'm'n'

The above highlights mean that:

The angles of both triangles are congruent

The triangles are similar

Next, we apply the rule on the coordinates of the triangle

L'' = 0.75 x 2 x (-1,2)

L'' = ( -1.5,3)

M'' = 0.75 x 2 x (-1,-1)

M'' = ( -1.5 , -1.5)

N'' = 0.75 x 2 x (2,-1)

N'' = (3 , -1.5)

Hence, the true statements are: The coordinates of n" are.

  • ∠m≅∠m'
  • Δlmn≅Δl'm'n'
  • The coordinates of n" are . N''(3,-1.5)

Read more about transformations at:

brainly.com/question/11709244

#SPJ1

6 0
2 years ago
HELP PICS INCLUDED! WILL GIVE BRAINLIEST! SHOW WORK AND EXPLAIN
Naddik [55]

I assume you know about the dot product, and that for two vectors \mathbf a and \mathbf b, the angle between them \theta satisfies

\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta\iff\cos\theta=\dfrac{\mathbf a\cdot\mathbf b}{\|\mathbf a\|\|\mathbf b\|}

Then the vectors are parallel if the angle between them is 0 or 180 degrees (0 or pi radians), which would make \cos\theta=1 or \cos\theta=-1, respectively.

Part A)

\vec v_1=\langle\sqrt3,1\rangle\implies\|\vec v_1\|=\sqrt{(\sqrt3)^2+1^2}=\sqrt4=2

\vec v_2=\langle-\sqrt3,-1\rangle=-\vec v_1\implies\|\vec v_2\|=\|\vec v_1\|=2

\vec v_1\cdot\vec v_2=(\sqrt3)(-\sqrt3)+(1)(-1)=-4

Then the angle between \vec v_1,\vec v_2 is such that

\cos\theta=\dfrac{-4}{(2)(2)}=-1\implies\theta=\pi\,\mathrm{rad}

so these vectors are parallel ("antiparallel", more specifically, which means they are parallel but point in opposite directions).

Part B) involves the same computations:

\vec u_1=\langle2,3\rangle\implies\|\vec u_1\|=\sqrt{2^2+3^2}=\sqrt{13}

\vec u_2 has the same components but differing by sign and order, as \vec u_1; its magnitude remains the same, though:

\vec u_2=\langle-3,-2\rangle\implies\|\vec u_2\|=\sqrt{(-3)^2+(-2)^2}=\sqrt{13}

\vec u_1\cdot\vec u_2=(2)(-3)+(3)(-2)=-12

\implies\cos\theta=\dfrac{-12}{(\sqrt{13})(\sqrt{13})}=-\dfrac{12}{13}\implies\theta=\cos^{-1}\left(-\dfrac{12}{13}\right)

which is neither 0 nor pi, which means these vectors are not parallel.

4 0
4 years ago
Ethan has has 3/4 of a box of cereal. He gives 1/8 of the box to his little brother and Ethan eats 1/4 of the box, himself. What
nalin [4]

Answer:

0

Step-by-step explanation:

3/4 - 1/4 = 2/4

2/4 - 1/4

get the same denominators

2/4 /2= 1/8

1/8 - 1/8= 0

There is nothing left in the cereal box.

6 0
4 years ago
Jeremy put pepperoni on half of a pizza. He put olives on 1/3 of the pizza. What fraction of the pizza did not have pepperoni?
evablogger [386]
1/2

he only put pepperoni on the other 1/2
6 0
3 years ago
Find the image of A(4, -2) after it is reflected over the line y = 2, then reflected over the line x = 2.
OleMash [197]
The reflection of (4,-2) over the line y = 2 is (4,6)
And then reflected over the line x = 2, the reflection is (0,6)

See image attached

8 0
3 years ago
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