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Thepotemich [5.8K]
3 years ago
13

Jeremy put pepperoni on half of a pizza. He put olives on 1/3 of the pizza. What fraction of the pizza did not have pepperoni?

Mathematics
1 answer:
evablogger [386]3 years ago
6 0
1/2

he only put pepperoni on the other 1/2
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Solve 4 | x + 7 |= 24.
Nana76 [90]

Answer: x = -1, -13

Step-by-step explanation:

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2 years ago
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What is the height of the tree in the figure to the nearest tenth of a foot?<br> h<br> 40°<br> 75 ft
Verizon [17]
I think that would be B 0.11
3 0
3 years ago
Please can someone help me answer these questions? Would be really grateful if it was done by the 12th of January. Thank you :)
FrozenT [24]
1. 4g= 37-5
 ⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8

2. c= 5*6
⇒ c= 30

3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.

4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0

5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17

6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7

7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9

8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8

9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0

10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24

11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3

12. x/3= 6-7
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⇒ x= -3

13. 6p= 2+1
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⇒ p= 3/6
⇒ p= 1/2

14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8

15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5

16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3

17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
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18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
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⇒ t+10= 4
⇒ t= 4-10
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Hope this helps~
6 0
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KATRIN_1 [288]

Answer:

Imagine that the number that we are looking for is x

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So the number we need is 435

8 0
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The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour
ikadub [295]
Mean = 12000
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We have to find how many standard deviations is 14,500 away from the mean.
This can be achieved by calculating the z-score

Z-score tells us how many standard deviations above or below is a sample value from the mean. A positive z value shows, sample value is above the mean.

z score can be calculated as = (Sample Value - Mean )/Standard Deviation)
So,
Z-score = \frac{14500-12000}{2000} =1.25

This means, 14,500 is 1.25 standard deviations above the mean value 12,000.
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3 years ago
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