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balandron [24]
3 years ago
7

Find the area of an equilateral triangle with a side of 10cm

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

Since it is an equilateral triangle, all sides are 10cm

Step-by-step explanation:

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Answer:

all work is shown and pictured

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Maths functions question
il63 [147K]

Answer:

-4 < x < 3

Step-by-step explanation:

<u>Information from Parts 1-4 of the same question:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)

<u>Information from Parts 5-8 of the same question:</u>

brainly.com/question/28193994

  • D = (-4, 7)

<h3><u>Part (9)</u></h3>

The values of x for which g(x) < f(x) are the values of x between the points of intersection of the two functions:  points D and A.

From part (2) of the question, we found that A = (3, 0).

From part (5) of the question, we found that D = (-4, 7).

Therefore, the values of x for which g(x) < f(x) are -4 < x < 3.

In interval notation this is: (-4, 3).

3 0
2 years ago
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Rewrite 8^(9/5) as a radical expression. I think it might be D, I'm unsure though.
AnnZ [28]
It is D, Nancy Reynolds from Chicago.

The denominator of the exponent is the index of the radical, the base of the exponent is the base of the radical, and the numerator of the exponent is the exponent of the radicand.

8^{\frac{9}{5}}= \sqrt[5]{8^9}
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3 years ago
100 POINTS! I am starving for help! Feed me an answer to this homeless guy!!!!!!!!!!!!!
stich3 [128]

Your answer is 288 dogs

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What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your
LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

y=27-x^2

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=27-x^2.

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

Area=Length\times width

Area=2x\times y

Substitute the value of y from the given equation.

Area=2x(27-x^2)

A=54x-2x^3      .... (1)

Differentiate with respect to x.

\frac{dA}{dx}=54-6x^2

Equate \frac{dA}{dx}=0, to find the critical points.

0=54-6x^2

6x^2=54

Divide both sides by 6.

x^2=9

x=\pm 3

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

A=54(3)-2(3)^3

A=162-54

A=108

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

7 0
3 years ago
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