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tino4ka555 [31]

3 years ago

12

Round 82.265 to the nearest whole number.

1 answer:

Zinaida [17]3 years ago

7 0

83.................................

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Has any see alexalunathis moring

Irina18 [472]

Answer:

no ill tell u if i see her homedawgidawg

Step-by-step explanation:

7 0

2 years ago

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Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

5 0

1 year ago

What is the x intercept of the function x^3-5x^2-8x+48

Zinaida [17]

Answer:

(x+3)(x-4)^2

Step-by-step explanation:

= (x+3)(x^3-5x^2-8x+48)/(x+3)

= x (x^3-5x^2-8x+48)/(x+3)

= x^2-8x+16

= (x+3)(x-4)(x-4)

= (x+3)(x-4)^2

4 0

2 years ago

Read 2 more answers

The age of the Hawaiian islands gets older as you move from east to west. If the half-life of K-40 is 1.3 billion years, approxi

Mumz [18]

Answer:

$t \approx 750550.12\,yr$

Step-by-step explanation:

The time constant of the isotope is:

$\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}$

$\tau \approx 1.876 \times 10^{9}\,yr$

The decay of the isotope is described by the following model:

$\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }$

Now, the time is cleared in the equation:

$t = -\tau \cdot \ln \frac{m}{m_{o}}$

$t = - (1.876\times 10^{9}\,yr)\cdot \ln 0.9996$

$t \approx 750550.12\,yr$

5 0

3 years ago

Anyone tell me the answer quick it is my homework

WITCHER [35]

Answer:

a. 8/24

divide denominator and numenator by three

1:3

b. 16/24

2:3

6 0

2 years ago