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3 years ago

Please help. Thanks. Work is due tomorrow. Thanks

Mathematics

1 answer:

eimsori [14]3 years ago

7 0

2 hole pizzas equal 16 because 1 pizza has 8 slices so make 1/4 a decimal which is 4 4/16 equals 4 so for 4 friends 1/4 is left and do the same to the 21/3 which equals 7 so 7 +4 = half the amount to fead the friends

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(no links or files) Solve this equation using the quadratic formula. This question should be solved both ways. (1) Quadratic For

meriva

Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3

Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2

4 0

2 years ago

What is the answer for 35 3/4 - 1/8

BabaBlast [244]

Steps:

1. since the least common multiple of 8 and 4 is 8, you would have to make both of the denominators 8.

2. 2 times 4 equals 8, 2 times 3 equals 6

3. 35 3/4 now becomes 35 6/8

4. your new problem is 35 6/8 - 1/8

5. 6 -1= 5

6. your answer is 35 5/8

4 0

3 years ago

An irrational number is one that simply can not be worked into any equation.

Fudgin [204]

Answer:

it can be use in equation

An irrational number is a number that cannot be expressed as a fraction for any integers and. . Irrational numbers have decimal expansions that neither terminate nor become periodic.

5 0

1 year ago

The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per

vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

Download pdf

4 0

3 years ago

Read 2 more answers

At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equatio

andriy [413]

The correct format of the question is

At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. $P = 400 ( 1.2 )^ t$ Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?

(A) 291

(B) 691

(D) 1440

Answer:

The increase in the population at the end of 2009 is 291 people

Step-by-step explanation:

We are given the equation as $P = 400 ( 1.2 )^ t$

where

P = No of People

t= No of Years

it is given that in the year 2006 the population is 400

this will only happen when we take t= 0

so for

Year value of t

2006- t = 0

2007- t = 1

2008- t = 2

2009 t = 3

No of people in 2009 will be

$P = 400(1.2)^3$

= 400*1.728

P = 691.2

Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691

Increase = P(2009) - P(2006)

= 691 - 400

= 291

The increase in the population at the end of 2009 is 291 people.

4 0

3 years ago