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Vitek1552 [10]
3 years ago
7

I neeeeeedddd help pls

Mathematics
2 answers:
Gre4nikov [31]3 years ago
6 0
I CAN HELP YOUUUUUUUUUUUUUUUUUU!!!!!!!!!!!!!!!!!!1

lets distribute 7(x+3)

so 7(x)+7(3)

7x+21  or b

yay :)

Digiron [165]3 years ago
5 0
The expression that is equivalent to 7(x + 3) is B. 7x + 21

Explanation:
This expression demonstrates the distributive property. For the distributive property, it tells us that we can remove the parenthesis if the term that the polynomial is being multiplied by is distributed to, or multiplied with each term inside the parenthesis .

Now let's go back to the problem

7(x + 3)

now by applying the Distributive Propery

7 * x + 7 * 3
The parentheses are removed and each term from inside is multiplied by the 7.

Now we can simplify the multiplication of the individual terms:

7x + 21
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On a manufacturer's assembly line, 3% of its merchandise comes off defective. If the company has 354 defective items, how many t
inysia [295]
11,800 items came off of the assembly line in total.

Divide the number of defective items by the percentage of total merchandise it accounts for to get the number of total items.

354 / 3% = 11800

3% = 0.03   ( percentage in decimal form )
8 0
4 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
Someone solve this please.
Archy [21]

Answer:

16x+2

Step-by-step explanation:

Perimeter- Length+width x2

(6x+4+2x-3)2

(8x+1)2

16x+2

6 0
3 years ago
8) Sumeya bought 2 packs of scrunchies for $31.75. How much
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Divide $31.75 by 2 to find out the cost for 1 pack. Then multiply that total times 3 to get the total for 3 packs.

31.75/2 = 15.875

15.875 x 3 = 47.625, rounded to $47.63
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3 years ago
How do I figure out 3x-r=r(-3+x)
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3x-r=-3r+rx
3x=-3r+r+rx
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there you go buddy...gitty up
3 0
3 years ago
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