If f is a one-to-one continuous function defined on an interval, then its inverse f−1 is also one-to-one and continuous.
Answer:10
Step-by-step explanation:
Dont know how to explain on here but I know for sure its 10 :)
Answer:
Step-by-step explanation:
d=m+a/n
Firstly, we multiply n to get rid of it by both sides. Since n is dividing a.
d=m+a/n
*n *n
dn=m+a
-m -m
a=dn-m