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AveGali [126]
2 years ago
14

Plz help me! I’m not sure how to do these!

Mathematics
1 answer:
Troyanec [42]2 years ago
7 0

Answer:

Step-by-step explanation:

Wait where is the picture

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Work out the size of the angle X.<br><br> Give your answer correct to 3 significant figures.
aleksley [76]

Step-by-step explanation:

Recall the Ratio for tan

Tan(theta) = opposite / adjacent

Tan (x) = 9 / 5

solve for x (use Tan^-1(...) )

3 0
2 years ago
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Carry out the following division.​
kifflom [539]

Answer:

1: 8a²

2: 9a²b²c²

Step-by-step explanation:

1: 48a³ ÷ 6a

48÷6 = 8

8a²

2: 72a³b⁴c⁵ ÷ 8ab²c³

72÷ 8 =9

9a²b²c²

4 0
2 years ago
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Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
You want too earn $100 to $120 per week . What are the possible numbers of hours that you can work at the sandwich shop so that
MAXImum [283]
Depends how much your job pays you
5 0
3 years ago
In the inequality, what are all the possible values of x?
Marat540 [252]

Answer:

B) \displaystyle x ≤ 0

Step-by-step explanation:

2(x + 12) − 16 ≤ 8

\displaystyle \frac{2(x + 12)}{2} ≤ \frac{24}{2} \\ \\ x + 12 ≤ 12 \\ \\ x ≤ 0

I am joyous to assist you anytime.

7 0
3 years ago
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