All categories

3 years ago

Find the measure of angle x in the figure below: A:35 B:48 C:69 D:78

Mathematics

1 answer:

anygoal [31]3 years ago

5 0

The best way to solve for x is to first solve for y and then subtract values. The top of "line" of the 3 angles togethers add up to 180 degrees. So from this, you can deduct this equation into $52+59+y=180$ . To solve for y, subtract $52$ and $59$ from the left hand side and rights hand side of the equation. now you know the value is $y=180-52-59=69$ . So the value of y is 69 degrees.
Now you know two angles of a triangle and the sum of the angles in a triangle is 180 degrees. So the equation is $x+69+63=180$ . To solve for x, subtract $69+63$ from both sides. $x=180-69-63=48$ . So you know that $x=48$ degrees.

You might be interested in

What is the area of the figure on the coordinate plane below?

Alex787 [66]

Answer:

A 144units ^ 2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the nth term of this sequence?

lions [1.4K]

Answer:

D, you simply just add 1.3 each time.

4 0

2 years ago

A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit

Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = - (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] = 20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0

3 years ago

If x + y= 2, x - y= 2 then x=

andriy [413]

Answer:

x374874593893

Step-by-step explanation:

eaddthemalltogethertogethtatjbifmwhumebry38578494029 aso add the m

6 0

3 years ago

Idk why I can’t get this ?! number two plz

Arturiano [62]

The only possible outcome to this would be any number greater or less than 361 in the 300’s

7 0

2 years ago