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Burka [1]
3 years ago
6

Desmos Introduction to Geometry Proofs Proof #5 Challenge

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

For statement 2, reason is Segment addition postulate.

Statement 3 and reason is

BD=AC+CD using substitution property of equality.

Statement 4 and reason is

AC+CD=BD using symmetric property of equality

Statement 5 is

BD= BC+CD

Statement 6 and reason is

AC+CD=BC+CD using transitive property of equality

Reason for 7 is

Subtraction property of equality.

Step-by-step explanation:

For statement 2, we use segment addition postulate to say AC= AE+EC.

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Ten times the square of a non-zero number is equal to sixty times the number.
Mice21 [21]
Let x be the nonzero number.
10 x^{2} =60x \\  \frac{1}{10x}(10 x^{2} =60x) \\ x=6
7 0
3 years ago
Read 2 more answers
A paintball court charges an initial entrance fee plus a fixed price per ball.
m_a_m_a [10]

Answer : The cost of 10 balls will be, 13.5 dollars

Step-by-step explanation :

As we are given the following expression:

P=0.80\times n+5.50

where,

P = total price (in dollars)

n = number of balls used

Given:

n = number of balls used = 10

Now we have to determine the cost of 10 balls.

P=0.80\times n+5.50

P=0.80\times (10)+5.50

P=8+5.50

P=13.5\$

Thus, the cost of 10 balls will be, 13.5 dollars

4 0
3 years ago
Evaluate the expression described below if the number is –2. The quotient of three less than twice a number and the number squar
lozanna [386]
<span>(2x-3)/x^2 
if the number is –2
then
[2(-2) - 3] / (-2)^2
= (-4-3)/4
= -7/4

answer is 
</span><span>D. -7/4</span>
4 0
2 years ago
Classify each pair of numbered angles.
kifflom [539]
Adjacent angles are angles with a common side and vertex, linear pairs are adjacent angles that are supplementary, and vertical angles are angles made by the same two lines but on opposite sides.

For the first one, 5 and 6 clearly do not share a side but they are made up by the same 2 lines and are opposite of each other, making them vertical.

For the next one, since the angles only share 1 line (and not a side) they can't be any of the above. 
5 0
3 years ago
Read 2 more answers
What is the solution to the inequality below?
Svetlanka [38]

Answer:

B. x < -8 or x > 8

Step-by-step explanation:

You can use process of elimination to solve this problem by going through every solution and testing them out, but let's jump right to B.

Process:

You know that since the inequality states that x^2 has to be greater than 64, x  has to be more than 8, or less than -8.

This is because 8^2 = 64, and -8^2 = 64, and the inequality requires the answer to be more than 64.

Looking at B., you can see that if x is < -8, the square of, for example, -9, would be 81. This is greater than 64, so this works!

Now, B. also has an alternative. The 'or' is a major clue to which is the correct answer, since the square root of any number can be positive or negative. (-8^2 = 8^2)

The 'or' states that x must be greater than 8. So, for example, if we take the square of 10, we get 100, and that is also greater than 64.

We've proven that this solution is accurate for both parts, so it is definitely the one we want!

Hope this helps!

4 0
3 years ago
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